Question 85006
Given f(x) = –x3 – 2x2 – x – 3

f(-2) , we plug in x = -2 in the above

f(-2) = -(-2)^3 - 2(-2)^2 - (-2) - 3

      = -(-8) - 2(4) -(-2) - 3
      = 8-8+2-3

     = 1

f(0) = -(0)^3 - 2(0)^2 - (0) - 3
     = -3

f(2) = -(2)^3 - 2(2)^2 - 2 - 3
     = -8 - 8 - 2 - 3

     = -21


Good Luck!!!