Question 992935
You would need to show all your steps.


You want to solve using substitution.
{{{system(4x-4y=-6,-x-2y=7)}}}


Simplest may be
{{{-x=2y+7}}}
{{{x=-2y-7}}}
Now substitute into the other equation.
{{{4(-2y-y)-3y=-6}}}
{{{4(-3y)-3y=-6}}}
{{{4(3y)+3y=6}}}
{{{15y=6}}}
{{{y=6/15}}}
{{{highlight(y=2/5)}}}


{{{x=-2(2/5)-7}}}
{{{x=-4/5-7}}}
{{{x=-4/5-35/5}}}
{{{highlight(x=-39/5)}}}