<PRE><B>Question 992893</B>
.
Let x be the middle of these three consecutive even integers.

Then the two others are (x-2) and (x+2).


The equation is 


{{{(x-2)/4}}} + {{{x/5}}} + {{{(x+2)/8}}} = 17.


Simplify: multiply by 40 both sides.


10*(x-2) + 8*x + 5*(x+2) = 17*40 = 680.


10x - 20 + 8x + 5x + 10 = 680,


23x = 680 + 20 - 10 = 690.


x = {{{690/23}}} = 30.


The numbers are 28, 30 and 32.


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