Question 992872
3x=1+sqrt(4x^2+x+7)
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3x-1 = sqrt(4x^2+x+7)
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Square both sides to get:
9x^2 -6x + 1 = 4x^2 + x + 7
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5x^2 - 7x - 6 = 0
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5x^2 - 10x+3x - 6 = 0
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5x(x-2)+3(x-2) = 0
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(x-2)(5x+3) = 0
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x = 2 or x = -3/5
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Cheers,
Stan H.
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