Question 992872
Can I get your help? My problem is this:

{{{3x=1+sqrt(4x^2+x+7)}}}

I started by subtracting the 1 from both sides which gave me {{{3x-1=sqrt(4x^2+x+7)}}} 
Now, would I add 4x^2 and x which would give me {{{sqrt (5x^3+7)}}} *********
No, you can't do that.  You can't add x^2 terms and x terms.
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{{{3x-1=sqrt(4x^2+x+7)}}} 
Square both sides
{{{9x^2 - 6x + 1 = 4x^2 + x + 7}}}
etc