Question 992635
Put the equation y=4x^2+7x+6 in vertex form and state the values of a, h, and k. Enter the exact answers. 
Vertex form= a(x-h)^2+k 
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y-6 = 4(x^2+(7/4)x)
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4(x^2+(7/4)x+(7/8)^2) = y - 6 +4(7/8)^2
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4(x+(7/8))^2 = y - 6 + 49/16
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4(x+(7/8))^2 = y-(47/16)
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y = 4(x+(7/8))^2 + (47/16)
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a = 4
h = -7/8
k = 47/16
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Cheers,
Stan H.
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