Question 992577


 a slope-intercept form equation for the line is 

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

given: the line passes through ({{{3}}},{{{3}}}) and has slope of {{{m=-2/5}}}

so far we have {{{y=-(2/5)x+b}}}

now use given point ({{{3}}},{{{3}}}) to find {{{b}}}

{{{3=-(2/5)3+b}}}

{{{3=-(6/5)+b}}}

{{{3+(6/5)=b}}}

{{{15/5+6/5=b}}}

{{{21/5=b}}}

{{{b=4.2}}}

so, your equation is: {{{y=-(2/5)x+4.2}}}