Question 992548
Two trains leave towns 614km apart at the same time and travel
toward each other. One train travels 11/kmh faster than the 
other. If they meet in 2 hours, what is the rate of each train?
<pre>
Let the slower train's speed be x km/h
Then the faster train's speed is x+11 km/h

Therefore their speed of approach is the sum of their speeds
or (x)+(x+11) or (2x+11) km/h.

Since {{{matrix(1,2,APPROACH,RATE)}}}{{{""=""}}}{{{DISTANCE/TIME}}}{{{""=""}}}{{{matrix(1,2,614,km)/matrix(1,2,2,hours)}}}{{{""=""}}}{{{matrix(1,2,307,km/h)}}}

So {{{2x+11}}}{{{""=""}}}{{{307}}}
    {{{2x}}}{{{""=""}}}{{{296}}}
        {{{x}}}{{{""=""}}}{{{148}}}

The slower train is traveling 148 km/h
The faster train is traveling 148+11 = 159 km/h

Edwin</pre>