Question 992532
 an electronic store sells about 70 of a new model of digital cameras per month at a proce of 320$ each. for each 20$ decrease in price, about 5 more cameras per month are sold. write a function that models the revenue. How many times should they lower the price by 20$ to maximize revenue. What price should they sell the camera to maximize revenue. How many cameras will they sell when they maximize revenue. What is the maximum revenue. 
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Revenue = (# of units sold)(price per unit)
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R(x) = (70+5x)(320-20x) = -100x^2 + 200x + 320*70
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R'(x) = -200x + 200
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Solve for "x"::
-200x + 200 = 0
x = 1
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Ans: To maximize Revenue
Sell at 320-20 = $300 per unit
# of units sold will be 70+5 = 75
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Cheers,
Stan H.