Question 992505

let number be {{{x}}}

if the difference between {{{1}}} more than {{{three}}} times a number is {{{17}}}, we have  

{{{(3x+1)-x=17}}}


{{{3x-x+1=17}}}

{{{2x=17-1}}}

{{{2x=16}}}

{{{x=16/2}}}

{{{highlight(x=8)}}}=> the smaller number

{{{3x+1=25}}}=> the larger number