Question 992322
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_{10}(2)\ =\ \frac{\log_2(2)}{\log_2(10)}\ =\ \frac{1}{\log_2(10)}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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*[tex \LARGE \ \ \ \ \ \ \ \ \ \