Question 992286
<font face="Times New Roman" size="+2">


Remember how to add fractions with different denominators.  You find the common denominator, convert, and add the numerators.  If the two denominators have no factors in common, then the lowest common denominator is simply the product of the two denominators.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 1\ +\ x}{x^2\ +\ x}\ =\ \frac{3}{2}]


Now you have a simple proportion.  Cross-multiply, collect like terms, and then solve the resulting quadratic.  Said quadratic is factorable and therefore has two real roots.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \