Question 992185
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You are doing the problem correctly, but I suspect you have an arithmetic error.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(1\ +\ \frac{0.04}{12}\right)^{12n}\ =\ 148.5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 12n\log(1.00333)\ =\ \log(148.5)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\ =\ \frac{\log(148.5)}{12\log(1.00333)}]


Check your calculator work; you should get 125 and change.


I figured out where you went wrong.  You rounded off too soon when you calculated *[tex \Large \left(1\ +\ \frac{0.04}{12}\right)]


Using 1.003 in the calculation gives you 139 and change.  Using 1.00333... to as many digits as your calculator will keep gives you 125.22+.  Object lesson:  Never round off until the last step in a multi-step calculation.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \