Question 992167
x + y = 12, where x is the tens digit and y is the units digit
x = y^2
substitute for x in first equation
y^2 + y - 12 = 0
factor the equation
(y-3)*(y+4) = 0
y = 3 or y = -4
x = 9 or x = 16
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we have one solution since we are looking for a two digit number
93