Question 84897
Let x=1st #, y=2nd #


Since we have 2 consecutive positive even integers, y=x+2. For instance, if our first number is 2, x=2. That means y=x+2=2+2=4. So we have

{{{xy=x(x+2)=120}}} "The product of two consecutive positive even integers is 120"

{{{x^2+2x=120}}}


{{{x^2+2x-120=0}}}


Now use the quadratic formula to solve for x

*[invoke quadratic "x", 1, 2, -120 ]

Since we're only looking for positive numbers, our first number is 10. So our second number is 


{{{y=10+2=12}}}

So our two numbers are 10 and 12