Question 992048
Please help with this question and provide the workings. 
Find an equation of the tangent line to the graph of the function f at the point (1, 15). f(x)=〖3x〗^2-11x+23
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f'(x) = 6x-11
f'(1) = -5
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Equation of line with m = -5 passing thru (1,15)
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Form:: y = mx + b
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Solve for "b"::
15 = 1*-5 + b
b = 20
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Equation 
y = -5x+20
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Cheers,
Stan H.
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