Question 991928
L, m, h for volume amounts of Low, medium, high in the order of 25, 45, 85.


{{{(25L+45m+85h)/160=40}}}; and {{{h/m=3}}}.  This lets to use {{{h=3m}}}, and this can be substituted into the percent equation:


{{{(25L+45m+85*3m)=40*160}}}

{{{(25L+300m)=4*16*100}}}

{{{L+12m=4*16*4*100}}}

{{{L+12m=100*16^2}}}-------This is one of the simplified equations or its equivalent, to use.


The other equation is the volume sum equation:
{{{L+m+h=160}}}
and according to the earlier described relationship among h and m,
{{{L+m+3m=160}}}
{{{L+4m=160}}}


Solve this system
{{{system(L+12m=25600,L+4m=160)}}}
You solve this system.