Question 991907
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Given that f(x) = {{{x^3}}} + {{{(10x)^1.5}}} + {{{1}}} find the value of f’(1).
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f'(x) = {{{3*x^2}}} + {{{1.5*(10x)^0.5*10}}}.


f'(1) = {{{3}}} + {{{1.5*sqrt(10)*10}}} = {{{3}}} + {{{1.5*3.162*10}}} = 50.43.