Question 991753
.
x and y are two numbers
.
{{{x^2+y^2=(x+y)^2}}}
{{{x^2+y^2=x^2+2xy+y^2}}}
{{{0=2xy}}}
{{{0=xy}}}
{{{x=0}}} {{{OR}}} {{{y=0}}}
ANSWER: Since one of the numbers is 0, the product is 0.