Question 84867
{{{(4u)/(9cd)  - (2c^3z^2)/(3ad^2) }}}


The first step is to find the LCD, which is {{{9acd^2}}}.


Multiply the first numerator and denominator by "ad", and the second numerator and denominator by "3c".  This brings each denominator up to the common denominator.  
{{{((4u)/(9cd))*((ad)/(ad))  - ((2c^3z^2)/(3ad^2))*((3c)/(3c)) }}}
{{{(4uad)/(9acd^2)  - (6c^4z^2)/(9acd^2) }}}
{{{(4uad-6c^4z^2)/(9acd^2) }}}
The numerator could be factored, but the fraction does not reduce so factoring is not necessary.


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