Question 991592

to find the slope and the {{{y}}} and {{{x}}} intercepts for {{{2x -3y = 18}}}, first write it in slope-intercept form {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

{{{2x -3y = 18}}}

{{{2x -18 = 3y}}}

{{{2x/3 -18/3 = 3y/3}}}

{{{y=(2/3)x -6}}}

so, the slope is {{{2/3}}} and y-intercept is {{{-6}}} or at point ({{{0}}},{{{-6}}})

now find x-intercept: set {{{y=0}}} and solve for {{{x}}}

{{{0=(2/3)x -6}}}

{{{0+6=2x/3 }}}

{{{6*3=2x }}}

{{{18=2x }}}

{{{x=18/2 }}}

{{{x=9 }}}=> x-intercept is {{{9}}} or at point ({{{9}}},{{{0}}})


{{{ graph( 600, 600, -10, 10, -10, 10, (2/3)x -6) }}}