Question 991590

let's numbers be {{{x}}} and {{{y}}}, and {{{x}}} is larger number
if the sum of two numbers is {{{50}}}, than we have

{{{x+y=50}}}......solve for {{{x}}}

{{{y=50-y}}}...........eq.1

if the larger number is {{{2}}} more than {{{5}}} times the smaller, we have

{{{x=5y+2}}}.....eq.2....now substitute {{{50-y}}} for {{{x}}} and solve for {{{y}}}

{{{50-y=5y+2}}}

{{{50-2=5y+y}}}

{{{48=6y}}}

{{{48/6=y}}}

{{{highlight(y=8)}}}

and the larger number is:

{{{x=5y+2}}}=>{{{x=5*8+2}}}=>{{{highlight(x=42)}}}