Question 991566
Complete the square to put into vertex form,
{{{y=4(x^2-3x)+5}}}
{{{y=4(x^2-3x+(3/2)^2)+5-4(3/2)^2}}}
{{{y=4(x-3/2)^2+5-9}}}
{{{y=4(x-3/2)^2-4}}}
Then factor to get to intercept form,
{{{y=(2x-5)(2x-1)}}}
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*[illustration rt1.JPG].