Question 991564
Factorize 15000 in 2 consecutive numbers whose difference is 2
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Factoring implies integers.
121*123 = 14883
122*124 = 15128
No integer solution.
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x*(x+2) = 15000
{{{x^2 + 2x - 15000 = 0}}}
*[invoke solve_quadratic_equation 1,2,-15000]
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