Question 991545
Hi dear,
Let the number be A,
From your first sentence,
{{{A=37[x]}}}-----(1)
From your second sentence,
{{{2A=75[x]}}}---(2)
put 1 in 2
{{{2(37[x])=75[x]}}}
From the above,
{{{2*(3*x^1+7*x^0)=7*x^1+5*x^0}}}
Then,
2(3x+7)=7x+5
6x+14=7x+5
7x-6x=14-5
x=9
The value of x is 9 
HOPE THIS HELPS?
Best wishes,
TIMNEWMAN.