Question 84861
{{{3y=(y-2)/(x-1)}}} Start with the given equation


{{{3y(x-1)=((y-2)/cross(x-1))cross(x-1)}}} multiply both sides by {{{x-1}}}


{{{3y(x-1)=y-2}}}


{{{3xy-3y=y-2}}} Distribute


{{{3xy-3y-y=-2}}} Subtract y from both sides


{{{y(3x-3-1)=-2}}} Factor out a y


{{{y*cross((3x-3-1)/(3x-3-1))=-2/(3x-3-1)}}} Divide both sides by {{{(3x-3-1)}}}


{{{y=2/(3x-3-1)}}}


{{{y=2/(3x-4)}}} Combine like terms


So our answer is


{{{y=2/(3x-4)}}}