Question 989965
{{{27x^3+8y^3=(3x+2y)(9x^2-6xy+4y^2)}}}
You can also show that,
{{{(3x+2y)^2=9x^2+12xy+4y^2}}}
{{{(3x+2y)^2-18xy=9x^2-6xy+4y^2}}}
So then,
{{{27x^3+8y^3=(3x+2y)((3x+2y)^2-18xy)}}}
Substituting,
{{{27x^3+8y^3=(12)((12)^2-18(6))}}}
{{{27x^3+8y^3=(12)(144-108)}}}
{{{27x^3+8y^3=432}}}