Question 991328
.
F=first=x; S=second=x+2; T=third=x+4; R=fourth=x+6
.
(3/4)(S+R)=(F+T)
(3/4)(x+2+x+6)=x+x+4
(3/4)(2x+8)=2x+4
3(2x+8)=4(2x+4)
6x+24=8x+16
8=2x
4=x
First=x=4
S=second=x+2=6
T=third=x+4=8
R=fourth=x+6=10
ANSWER: The numbers are 4,6,8, and 10.
.
CHECK:
(3/4)(S+R)=(F+T)
(3/4)(6+10)=(4+8)
(3/4)(16)=12
12=12