Question 84850
So first the quadratic formula is:

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

For our problem, it says {{{x^2-x+6=0}}} . The generaly formula for the quadratic equation is {{{ ax^2 + bx + c =0}}} therefore it means that in our case, a=1 , b= -1, and c=6 .

From here, we can plug these values into the formula to make it look like:

{{{(-(-1) +- sqrt( (-1)^2-4*1*6 ))/(2*1) }}} 

When we simplfy this we first get:

{{{ 1 +- sqrt((1-24))/(2*1) }}}

At this point it becomes clear that your problem does not have a solution since we cannot take the {{{sqrt(-23)}}} because we cannot take the square root of negative numbers.