Question 991385
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Find the center and radius of the circle: x^2+y^2-4x+10y-3=0
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{{{x^2+y^2-4x+10y-3}}} = {{{0}}},


Transform to an equivalent expression by completing full squares:


{{{(x-2)^2 -4 +(y+5)^2 - 25 - 3}}} = {{{0}}},


{{{(x-2)^2 + (y+5)^2}}} = {{{3+25+4}}},


{{{(x-2)^2 + (y+5)^2}}} = {{{32}}}.


It is the circle of the radius  r = {{{sqrt(32)}}} = {{{4sqrt(2)}}} with the center at the point  (2,-5).