Question 991377
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1. {{{a[1]}}} = {{{3}}},


{{{a[6]}}} = {{{a[1]*q^5}}},


{{{q^5}}} = {{{a[6]/a[1]}}} = {{{96/3}}} = {{{32}}} = {{{2^5}}},


{{{q}}} = {{{root(5,32)}}} = {{{2}}}.


2. {{{a[11]}}} = {{{3*2^10}}} = {{{3*1024}}} > {{{3000}}}.


{{{a[10]}}} = {{{3*2^9}}} = {{{3*512}}} < {{{3000}}}.


n = 11.