Question 991247

{{{w(w+17)=110}}}


{{{w^2+17w=110}}}


{{{w^2+17w-110=0}}}

{{{w^2-5w+22w-110=0}}}

{{{(w^2-5w)+(22w-110)=0}}}

{{{w(w-5)+22(w-5)=0}}}

 {{{(w-5)(w+22) = 0}}}

solutions:

if {{{(w-5) = 0}}}=>{{{w=5}}}
if {{{(w+22) = 0}}}=>{{{w=-22}}}=> disregard negative solution because we are looking for width

so, our solution for width is {{{highlight(w=5)}}}

now find the length: {{{w+17=5+17}}}=>{{{highlight(w+17=22)}}}