<PRE><B>Question 991206</B>
You have a set of 3 integers, each one being 3 higher than the previous one. The sum of the second and third integers is 1 more than 4 times the first integer. 
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1st:: x
2nd: x + 3
3rd: x + 6
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Equation:
x+3 + x+6 = 4x+1
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2x+9 = 4x+1
2x = 8
x = 4 (1st)
x+3 = 7 (2nd)
x+6 = 10 (3rd)
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Cheers,
Stan H.
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