Question 991210
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Note that the *[tex \Large y]-intercepts of the two lines are *[tex \Large (0,5)] and *[tex \Large (0,-5)].  Since the circle is centered at the origin and has a radius of 5, the two intercepts are on the circle.  So that is two of your vertices.  The third has to be the intersection of the two lines.  Solve the 2X2 system for the coordinates of the intersection.


*[illustration TriangleInCircle.jpg].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \