Question 991014
S = 2(pie)rH + 2(pie)r(squared) for H
S = {{{(2*pi*r*h) + (2*pi*r^2)}}}
we can write it like this
{{{(2*pi*r*h) + (2*pi*r^2)}}} = S
subtract {{{2*pi*r^2}}} from each side
{{{(2*pi*r*h)}}} = {{{S - (2*pi*r^2)}}}
Divide both sides by {{{2*pi*r}}}
h = {{{(S-(2*pi*r^2))/(2*pi*r)}}} = {{{S/(2*pi*r)}}}-{{{((2*pi*r^2))/(2*pi*r)}}}
Cancel {{{2*pi*r)}}} in the 2nd fraction and you have
h = {{{S/(2*pi*r)}}} - r