Question 991064
{{{Y=3x^2-48}}}

{{{Y=3(x^2-16)}}}

{{{Y=3(x^2-4^2)}}}

{{{Y = 3 (x-4)(x+4)}}}

roots:

{{{3 (x-4)(x+4)=0}}}, since {{{3<>0}}} it is not a root, so only value of {{{x}}} that makes {{{(x-4)(x+4)=0}}} will be the roots

if {{{ (x-4)=0}}}=>{{{x=4}}}
if {{{(x+4)=0}}}=>{{{x=-4}}}

{{{ graph( 600, 600, -10, 10, -55, 10, 3(x^2-4^2)) }}}