Question 990993
William has $4.20 in his bank in nickels, dimes and quarters. HE has 44 coins total. The number of nickels is one more than twice the number of dimes. Find the number of each kind of coin he has in the bank.

let x=number of dimes
2x+1=number of nickels
44-(x+2x+1=44-3x-1=43-3x=number of quarters
.10x+.05(3x+1)+.25(43-3x)=4.20
.05+10.80-.55x=4.20
.55x=6.60
X=12                                                                             
number of dimes=12
number of nickels=25
number of quarters=7