Question 990867
sue has $1.95 in dimes and nickels. If she has 9 more dimes as nickels, how many of each coins does she have? 
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Put the "9 more dimes" aside --> pairs of dimes and nickels worth $1.05.
They're 15 cents each
105/15 = 7 pairs
--> 7 nickels & 16 dimes
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The hard way:
d = n + 9
10d + 5n = 195
Solve for d and n