Question 990791


x + (x + 1) + (x + 2) = 111 --> x + x + 1 + x + 2 = 111


3x + 3 = 111


3x = 111 - 3


3x = 108


3x/3 = 108/3


x = 36


Therefore, 36 + 37 + 38 = 111 are your three consecutive numbers.


Verify: 


x + (x + 1) + (x + 2) = 111 ---> 36 + (36 + 1) + (36 + 2) = 111


36 + 37 + 38 = 111


111 = 111