Question 990636
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Since you didn't specify a method, here is Gauss-Jordan row reduction.

<pre>
 1    1    -1    0
 2   -1     1    3
-1    5    -3    2

 1    1    -1    0    -2R1 + R2 to R2
 0   -3     3    3
-1    5    -3    2

 1    1    -1    0    -R1 + R3 to R3
 0   -3     3    3
 0    6    -4    2

 1    1    -1    0    -R2/3 to R2
 0    1    -1   -1
 0    6    -4    2

 1    1    -1    0    -6R2 + R3 to R3
 0    1    -1   -1
 0    0     2    8

 1    1    -1    0    R3/2 to R3
 0    1    -1   -1
 0    0     1    4

 1    1     0    4    R3 + R1 to R1
 0    1    -1   -1
 0    0     1    4

 1    1     0    4    -R2 + R1 to R1
 0    1     0    3
 0    0     1    4

 1    0     0    1    R3 + R2 to R2
 0    1     0    3
 0    0     1    4
</pre>

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \