Question 990491


Hello,


Given: Ray OB bisects segment EF


Prove: 2(EO) = EF


Ray OB bisects segment EF (given)


EO = OF (segment bisector contains midpoint (O) of the segment)


EO + OF = EF (segment addition postulate, AB + BC = AC)


EO + EO = EF (Substitution *EO = OF or OF = EO)


2(EO) = EF (Simplify by means of addition)