Question 989507

Suppose "n" is a number.


Five times the difference of a number and three: 5(n - 3)


...is four less than four times the number: 4n - 4


The equation: 5(n - 3) = 4n - 4


Solve, 

5(n - 3) = 4n - 4 


5n - 15 = 4n - 4  ---> 5n - 4n = 15 - 4


n = 11


Verify:

5(n - 3) = 4n - 4 --> 5(11 - 3) = 4(11) - 4  --> 40 = 40



Thus, n = 11 is the number.