Question 990674
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Hello,


1.  Your conclusion that  y=0  is correct.


2.  For  x  and  z  we have only one equation  (one constrain)  5x + z = 0.


It means that &nbsp;<B>z</B>&nbsp; can be anything, &nbsp;but &nbsp;<B>x</B>&nbsp; must be &nbsp;{{{-z/5}}}.


Or, &nbsp;in other words, &nbsp;<B>x</B>&nbsp; can be anything, &nbsp;but &nbsp;<B>z</B>&nbsp; must be &nbsp;{{{-5x}}}.


Thank you for asking.