Question 990422
All the sides are equal to each other.
{{{4a-b=b+a}}}
{{{3a-2b=0}}}
1.{{{3a=2b}}}

.
.
.
{{{b+a=2b-4}}}
2.{{{a=b-4}}}
So then
{{{3a=3b-12}}}
Substituting from 1,
{{{2b=3b-12}}}
{{{b=12}}}
and
{{{3a=2(12)}}}
{{{3a=24}}}
{{{a=8}}}