<PRE><B>Question 84766</B>
&lt;pre&gt;&lt;font size = 4&gt;&lt;b&gt;
When the constraint 6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; &lt;u&gt;&lt;&lt;/u&gt; 28 
is converted to an equation, the equation is

A. 6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; = 28
B. 6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; - 28 = 0
C. 6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; + s&lt;sub&gt;1&lt;/sub&gt; = 28
D. 6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; - s&lt;sub&gt;1&lt;/sub&gt; = 28

6x&lt;sub&gt;1&lt;/sub&gt; + 17x&lt;sub&gt;2&lt;/sub&gt; &lt;u&gt;&lt;&lt;/u&gt; 28

When the left side is less than the right side 28, then
a positive number must be added to the left side to &quot;take
up the slack&quot; between the smaller left side and the larger
right side.  So we add a &quot;slack variable&quot; s&lt;sub&gt;1&lt;/sub&gt; to
the left side as the proper positive number that will
&quot;take up the slack&quot; between the smaller left side and the 
larger right side.  [No harm is done when the left side 
exactly equals the right side because in that case s&lt;sub&gt;1&lt;/sub&gt; 
just becomes 0].  So the only choice which adds s&lt;sub&gt;1&lt;/sub&gt;
to the left side is choice C.

Edwin&lt;/pre&gt;</PRE>