Question 990525

Let x + (x + 1) + (x + 2) = 99 --> x + x + 1 + x + 2 = 99


Adding will yield, 3x + 3 = 99 


3x + 3 = 99 --> 3x = 99 - 3 --> 3x = 96


3x/3 = 96/3 


x = 32 


The 3 consecutive numbers are 32, 33, 34.


Verify:

32 + 33 + 34 = 99