Question 990392
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2}{3}x\ +\ x\ +\ (x\ -\ 9)\ =\ 71]


Solve for *[tex \Large x], then calculate *[tex \Large \frac{2}{3}x] and *[tex \Large x\ -\ 9]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \