Question 990299
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Solved for consecutive odd integers:
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S=smaller integer; L=larger integer=S+2
{{{S*L=6S+5}}}
{{{S(S+2)=6S+5}}}
{{{S^2+2S=6S+5}}}
{{{S^2-4S-5=0}}}
{{{S-5)(S+1)=0}}}
{{{S-5=0}}} {{{OR}}} {{{S+1=0}}}
{{{S=5}}} {{{OR}}} {{{S=-1}}}
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For S=5:
L=S+2=5+2=7
ANSWER: The numbers are 5 and 7.
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For S=-1:
L=S+2=-1+2=1
ANSWER: The numbers are -1 and 1.