Question 989864
Let {{{ w }} = the width in ft
{{{ 2w - 6 }}} = the length in ft
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{{{ A = ( 2w - 6 )*w }}}
{{{ 216 = ( 2w - 6 )*w }}}
{{{ 216 = 2w^2 - 6w }}}
{{{ 2w^2 - 6w - 216 = 0 }}}
{{{ w^2 - 3w - 108 = 0 }}}
I notice that {{{ 108 = 9*12 }}}
and {{{ 12 - 9 = 3 }}} , so I'm guessing . . .
{{{ ( w - 12 )*( w + 9 ) = 0 }}}
{{{ w = 12 }}}
This is the answer since width can't be negative
{{{ 2w - 6 = 2*12 - 6 }}}
{{{ 2w - 6 = 18 }}}
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check answer:
{{{ A = 12*18 }}}
{{{ A = 216 }}}
OK