Question 82281
x = y^2 ---------------(1)
(x + 3)^2 + y^2 = 53 --(2)

(1) + (2): x + (x + 3)^2 = 53

x + x^2 + 6x + 9 = 53

x^2 + 7x - 44 = 0

(x + 11)(x - 4) = 0

x = -11 
x = 4

Discard x = -11 because you cannot square root a negative number to get a real number answer. Looking at (1): y^2 = -11; this will give you an imaginary number.

Therefore, y = 2 or -2 because y^2 = 4.